Sealing rings are common parts in mechanical equipment, and their role is to prevent liquid or gas leakage. In the actual use process, the compression of the sealing ring is an important parameter, which directly affects the sealing performance of the equipment. So, if we want the seal compression to reach 20%, how much pressure do we need to apply?

First, we need to understand how the compression of the sealing ring is calculated. In general, the compression of the seal refers to the difference between its initial height and the height after installation, which is generally expressed in the form of % (percentage). For example, a sealing ring with an initial height of 10 mm and a height of 8 mm after installation has a compression of 20%.

So, how much pressure is needed to make the compression of the seal ring reach 20%? The problem is complicated because different types and sizes of seals require different pressures. In general, the compression of the sealing ring is proportional to the pressure applied, that is, the greater the pressure, the greater the compression.

To simplify the calculation, we can estimate the required pressure using the following formula:

P = F / A

Where P represents the required pressure, F represents the force applied to the sealing ring, and A represents the contact area of the sealing ring. According to this formula, we can calculate the required pressure and choose the appropriate tools and equipment to apply the force.

It should be noted that applying too much pressure may cause deformation or damage to the sealing ring, so it needs to be handled carefully in actual operation. At the same time, in order to ensure the good sealing performance of the equipment, the adjustment and installation of the seal ring is also required to operate in strict accordance with a series of standards and requirements.